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If the straight line ax+by+c =0 always passes through (1,-2) then a,b,c are in

1.ap

2.gp

3. hp

4. none of these

2
by stswati14

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1.ap

2.gp

3. hp

4. none of these

by stswati14

Log in to add a comment

hence the value of x = 1 and y =-2

therefore from Eqn ,

a(1)+b(-2)+c = 0

⇒ a-2b+c = 0

⇒a+c = 2b

so, b= (a+c)/2

therefore a, b ,c are in A.P

Hence x=1 and y=-2

now, a(1)+b(-2)+c=0

a-2b+c=0

a+c=2b

Hence a, b, c are in A.P