Answers

2014-03-07T10:50:34+05:30
Say the four numbers be a,(a+d),(a+2d),(a+3d)<span>
sum =4a+6d=20</span><span>      
2a +3d=10</span><span>
Sum of squares =
a^2+(a^2 +2ad +d^2)+(a^2 +4ad + 4d^2)+(a^2+6ad +9d^2)= 4a^2+12ad+14 d^2=120 plug
2a=10-3d</span><span>
(10 - 3d)^2+6d (10-3d)+14d^2=120<span> 
100 -60d +9d^2 +60d -18d^2+14d^2 = 120<span>
5d^2 =20</span><span>
d=2<span>   a=2</span><span>     
The numbers are
2,4,6,8</span><span>



















1 5 1
2014-03-07T14:20:08+05:30
=A+P=20
=A=20-p........................i
 =(A+P)^2=120
sunstiturw value of equatino i to formula.
(20-P+P)^2=120 
done
                        
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