Find the time in which Rs.1200 will amount to Rs.1536 at 3.5%per year.
What sum of money borrowed on 24th May will amount to Rs.10210.20 on 17th October of the same year at 5% per annum simple interest

plz fast all simple interst sums.

2
it is not correct to engage in arguments on comment lines. avoid it please.
.....sorry

Answers

2014-09-28T15:10:39+05:30
1.Principal=Rs.1200
Amount=Rs.1536
Rate=3.5%p.a. Interest=A-P=Rs.1536-Rs.1200=Rs.336
Using SI=P*R*T/100 we get,
T=100*SI/(P*R)=100*336/(1200*3.5)
or,T=33600/4200
or,T=8
Ans:The required time is 8 years.
2.Amount=Rs.10210.2
Rate=5% p.a.
Time(in days)=(31-24)+30+31+31+30+17=146 
146 days=146/365 years=2/5 years
Using A=P(1+RT/100) ,we get        (this formula is a handy one)
P=100*A/(RT+100)
or,P=100*10210.2/(2/5*5+100)
or,P=1021020/102
or,P=10010
Ans:The required principal is Rs.10010
2 5 2
how dare youuuuuuu!!!!!!!!!!!!!!!!!(goes to singhsumita) You must have guessed it!!!!!!
Kvnmurty's answer is good he must have done it with a graph paper
baccha kisko bola???
hahahahahahaha!! A class 8 student asking S.I. Q/ANS AS if he/she can't do
i dont have graph paper. i did it here. thanks. do not argue on comment lines.
2014-09-29T00:13:06+05:30

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Assume it is simple interest. So total interest = Rs 1,536 - Rs 1,200 = Rs 336
n = number of years

336 = P r n = 1200 * (3.5 /100 ) * n
n = 28/3.5 = 8 years
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Simple interest.
Number of days = 7 may +30 june +31 july +31 aug +30 sept +17 oct = 146 days
P ( 1 + r n ) = Rs 10,210.20 
P = 10,210.20 / [1 + (5/100) * (146/365)] = 10,210.20/1.02 = Rs 10,010.
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