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THE CURVED SURFACE AREA OF A CYLINDER 4400CM2AND CURCUMFERENCE OF ITS BASE IS 110CM .FIND THE VOLUME OF ACYLINDER.

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by sravas

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by sravas

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r² = 110×7/22

≈6

2rh = 4400

2×22/7×6×h=4400

h = 100×7/6

=700/6

=116.7

V = r²h

=22/7×6²×116.7

=13203.77

110/2 = 22/7*r

55 = 22/7*r

55*7/22 = r

35/2 = r

Curved surface area of the cylinder =

4400 = 2*22/7*35/2*h

4400 = 22*5

4400/110 = h

4 = height

Volume of a cylinder =

Volume of the cylinder = 22/7*4*35/2*35/2

Volume of the cylinder = 3850