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if d is HCF of 40and 65,find the

value of integers X and Y which

satisfy d=40x+65y i am not getting the answer !!!

2
by anaisha

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value of integers X and Y which

satisfy d=40x+65y i am not getting the answer !!!

by anaisha

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D= 5 so

x=1/8,y=0

or

x=0,y=1/13

and many more such solutions...

x=1/8,y=0

or

x=0,y=1/13

and many more such solutions...

d=40x+65y

5=40x+65y

so

by this we can assume the values of x,y

there are 2 possibilitiesof x,y.

1] x=0,y=1/13

2] x=1/8,y=0