Sum of three consecutive intergers is 48. find the even number

2
one number is even=2x.
one number is even=2x
other 2 are odd= (2x+1) and (2x-1)
so, (2x+1) + 2x + (2x-1)=48
2x+2x+2x=48
6x=48
x=8.
so the three numbers are= 15,16,17.
Let first no. be x. Then second would be x+1 and third would be x+2 .
Now, x+(x+1)+(x+2)=48
i.e. 3x+3=48
or,3x=48-3=45
Therefore, x=15
So, the three consequtive numbers are 15,16,17 out of which only 16 is even.

Answers

2014-01-04T13:20:36+05:30
2014-01-04T13:47:57+05:30
Let the consecutive integers be x,x+1,x+2 so x+x+1x+2=48 then x=15 so numbers are 15,16,17 so the even number is16
0