# Car A takes 1 hour less than car B to cover a distance of 132 km. if the average speed of car Ais 11km/hr more than that of car B, formulate the quadratic equation

2
by danerstiker47

2014-10-01T16:46:15+05:30

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Let average speed of car B = x km/h
average speed of car A = (x+11) km/h

To cover 132 km,
time taken by car B = 132/x hours
time taken by car A = 132/(x+11) hours

Now
= 1
⇒132() = 1
⇒132() = 1
⇒132() = 1
= 1
⇒x² + 11x = 1452
⇒x² + 11x -1452 = 0
2014-10-02T13:32:28+05:30
the avg speed of B be x
then the avg speed of A=x+11

the distance covered=132 km
time taken by A=132/(x+11)
time taken by B=132/x
ATQ ,
(132/x)-132/(x+1)=1

solving this we will get
x²+11x=1452
⇒x²+11x-1452=0
which is the required quadratic eqn