with all the steps plz

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with all the steps plz

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(a+b+c)²

=(a+b+c) × (a+b+c)

=[a×(a+b+c)] + [b×(a+b+c)] +[c×(a+b+c)] (by distributive law)

= [a² + ab + ac] + [ ba +b² + bc] + [ ca + cb + c²]

= a² + ab + ac + ba +b² + bc + ca + cb + c²

= a² + ab + ac + ab +b² + bc + ac + bc + c² (ab=ba)

= a² + b² + c² + ab + ab + bc + bc + ac + ac

= a² + b² + c² + 2ab + 2bc + 2ca

=(a+b+c) × (a+b+c)

=[a×(a+b+c)] + [b×(a+b+c)] +[c×(a+b+c)] (by distributive law)

= [a² + ab + ac] + [ ba +b² + bc] + [ ca + cb + c²]

= a² + ab + ac + ba +b² + bc + ca + cb + c²

= a² + ab + ac + ab +b² + bc + ac + bc + c² (ab=ba)

= a² + b² + c² + ab + ab + bc + bc + ac + ac

= a² + b² + c² + 2ab + 2bc + 2ca

let a+b=x ,c=y

substitute the values in the equation

(x+y)²=x²+y²+2xy

(a+b)²+c²+2c(a+b)

a²+b²+2ab+c²+2ac+2bc

a²+b²+c²+2ab+2bc+2ca