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A ball is thorn vertically upward by speed of 12m/s in 8 then how much distance will it cover.

2
what is this "of 12m/s in 8 " ?

in 8sec

and g = ?

10 m/s2 or 9.8m/s2

??

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what is this "of 12m/s in 8 " ?

in 8sec

and g = ?

10 m/s2 or 9.8m/s2

??

Log in to add a comment

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Initial velocity(u)= 12 m/s

time = 8 sec

let s be the height

so using

when g = 10 m/s²

s = 12×8 + 1/2 × 10 × 64

s = 96 + 320

s = 416 m

so the height reached is 416 m

when

g = 9.8 m/s²

s = 12×8 + 1/2 × 9.8 × 64

s = 96 + 313.6

s = 409.6 m

time = 8 sec

let s be the height

so using

when g = 10 m/s²

s = 12×8 + 1/2 × 10 × 64

s = 96 + 320

s = 416 m

so the height reached is 416 m

when

g = 9.8 m/s²

s = 12×8 + 1/2 × 9.8 × 64

s = 96 + 313.6

s = 409.6 m

t = 8 s

'g' will be 10 m/s²

s = ?

s = ut + 1/2gt²

= 12×8+1/2×10×8²

= 96+5×64

= 96+320

=416 m

Distance will be 416 m.