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2014-10-04T16:04:41+05:30

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Charges are 5μC and -20μC.
Distance between them = 30cm =0.3 m
r = 0.3/2 = 0.15 m
Strength of field at midpoint =  \frac{1}{4 \pi e}  \frac{( q_{1} )}{ r^{2} } +  \frac{ q_{2} }{ r^{2} } ]

                         =   \frac{1}{4 \pi e}  \frac{( 5*10^{-6} )}{ 0.15^{2} } -  \frac{ 20*10^{-6} }{ 0.15^{2} }

                         = (9×10^9)  [ \frac{( 5*10^{-6} )}{ 0.15^{2} } -  \frac{ 20*10^{-6} }{ 0.15^{2} } ]

                         =  -6*10^{6} N


             



                                            
           
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it is not in options
options are A)10^9N/C B)10^-7N/C C)10^7N/C D)10^-9N/C