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2014-10-04T22:51:56+05:30

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X-y = 4
x = y+4

xy=192
(y+4)y = 192
y² + 4y - 192 = 0
(y-12)(y+16)=0
y = 12
x = 16

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2014-10-04T23:20:24+05:30
Let us consider and b are two numbers
given that a-b=4 equation 1
and ab=192
according to
(a+b)^2 - (a-b)^2 = 4ab
substitute above values in above formula
then we get
(a+b)^2 - (4)^2 = 4*192
(a+b)^2 - 16 = 768
(a+b)^2 = 768 + 16 = 784
a+b = square root(784)
a+b = 28 equation 2
subtract equation 2 and equation 1
we get 2b= 24
b = 12
then b=18 substitute in equation 2 then a = 28-12 = 16
therefore the two numbers are 16 and 12
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