plz try to give space

Log in to add a comment

plz try to give space

Log in to add a comment

EX: 5+7+7+7

5 SHEEP IN 1ST PEN

7 SHEEP IN 2ND PEN

7 SHEEP IN 3RD PEN

7 SHEEP IN 4TH PEN

divide 26 with 4

we get 6·5

so first we can have 6 sheep in all pens with 2 left

first:6+3

second:6-3

third:6-1

fourth:6+1

now,

first:9

second:3

third:5

fourth:7

remaining two can be added to any of the pen

now,

first:9

second:5

third:5

fourth:7

i added the 2 to second pen

so, here's the answer