# Five years hence , father's age will be three times the age of his son. Five years ago , father was seven times as old as his son . Find their present ages.

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by dweejareddy

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by dweejareddy

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Let father's age = x

son's age = y

Five years hence, age of father = x+5

age of son = y+5

So (x+5) = 3(y+5)

⇒ x =3y+10

Five years ago, age of father = x-5

age of son = y-5

So x-5 = 7(y-5)

⇒3y + 10 - 5 = 7y - 35

⇒ 4y = 40

⇒y = 10 <<<<<<<<son's age

x = 3y +10 = 40 <<<<<<father's age

son's age = y

Five years hence, age of father = x+5

age of son = y+5

So (x+5) = 3(y+5)

⇒ x =3y+10

Five years ago, age of father = x-5

age of son = y-5

So x-5 = 7(y-5)

⇒3y + 10 - 5 = 7y - 35

⇒ 4y = 40

⇒y = 10 <<<<<<<<son's age

x = 3y +10 = 40 <<<<<<father's age