Answers

2014-10-05T20:27:58+05:30
Sum of digits of two-digit number=132
let the no. be x
x+12=132/5
x=132/5-12
x=132/5-60/5
x =72/5

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2014-10-05T21:19:02+05:30
Let the number be 10y+x    i.e the digit at ten's place is y and that in one's place is x
given 10y+x + 10x+y=132 ---------1
also given 10y+x + 12=5(x+y) which gives 10y+x=5(x+y)-12 ---------2
sub. 2 in 1
5(x+y)-12+10x+y=132
solving the above equation for x, you will get  x=(48-2y)/5 ------3
sub. 3 in 1
10y+ (48-2y)/5 + 10(48-2y)/5 +y=132
solving the above equation for y, you will get  33y=132 which gives y=4 --------4
sub. 4 in 3 
you will get x=8
so the number is 10y+x= 10(4)+8=48
there you go ^_^
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