# Calculate the power of an electric engine which can life 20 ton of coal per hour from a mine 180 metre depth.

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by kaushikabhi

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by kaushikabhi

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Mass = 20,000kg

weight (F)= 20,000 × 10 N = 2×10⁵ N

depth = 180m

time = 1hr =3600s

velocity = 180/3600 = 0.05m/s

Power = force×velocity = 2×10⁵×0.05 = 10000 W = 10kW

weight (F)= 20,000 × 10 N = 2×10⁵ N

depth = 180m

time = 1hr =3600s

velocity = 180/3600 = 0.05m/s

Power = force×velocity = 2×10⁵×0.05 = 10000 W = 10kW

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

I take a ton as a metric ton or tonne equal to 1000 kg weight.

mass of coal transported to a height of 180 meters in one hour

= 20 metric tons = 20,000 kg

Change in the potential energy of coal : m g h

= 20,000 kg * 9.81 m/sec² * 180 m = 35,316 kJoules

Power supplied by the electric engine = Energy supplied / time duration

= 35,316 kJ / 3600 sec = 9.81 kW

Power = 10 kW if g is taken as 10 m/sec²

mass of coal transported to a height of 180 meters in one hour

= 20 metric tons = 20,000 kg

Change in the potential energy of coal : m g h

= 20,000 kg * 9.81 m/sec² * 180 m = 35,316 kJoules

Power supplied by the electric engine = Energy supplied / time duration

= 35,316 kJ / 3600 sec = 9.81 kW

Power = 10 kW if g is taken as 10 m/sec²