# A number consists of two digits. When it is divided by the sum of the digits, the quotient is 7. If 27 is subtracted from the number, the digits are reversed. Find the number.

2
by dweejareddy

Log in to add a comment

by dweejareddy

Log in to add a comment

So when it is divided by the sum of the digit, the quotient is 7 :-

10x + y / x + y = 7 so,

3x - 6y = 0 ----------( equation 1)

Then, If 27 is sub from the no the digits are reversed:

10 x + y - 27 = 10 y + x

x - y = 27 ------------( equation 2)

Multiply Eq (1) and Eq (2), we get,

3x - 3y = 9-------------( 3)

Sub Eq (1) and (), we get

3x - 6y = 0 - ( 3x - 3y = 9)

= 3y = 9

y = 9/3

= 3

( y = 3)-------( 4)

Put (4) in (2)

x - 3 = 27

x = 6

( x = 6)

So the number is 63

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Let x is the tenth digit and y is unit digit.

then the number is 10x+y.

When it is divided by sum of the digits, quotient is 7

thus

⇒

⇒

⇒

⇒

When 27 is subtracted from it, digits are reversed(y comes to tenth place and x goes to unit place), thus

⇒

⇒

⇒ (dividing by 9)

⇒

⇒

⇒

⇒

The number is 10x+y = 10*6+3 =**63**

then the number is 10x+y.

When it is divided by sum of the digits, quotient is 7

thus

⇒

⇒

⇒

⇒

When 27 is subtracted from it, digits are reversed(y comes to tenth place and x goes to unit place), thus

⇒

⇒

⇒ (dividing by 9)

⇒

⇒

⇒

⇒

The number is 10x+y = 10*6+3 =