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The base and height of a parallelogram are in the ratio 5:3 if the area is 50m sq . find its altitude

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by ultrab30

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by ultrab30

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as we know that area=base×height

here are a 50 m sq

so 50 m sq= 5x×3x

=50 m sq=15x²

x²=50/15

so x =1.82

lets substitute the x value in base

so 5×1.82=9.1 (approx)

and height= 3×1.82=5.46 (approx)

therfore base =9.1 and height=5.46

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Area of a parallelogram is equal to base * altitude

base : altitude = 5 : 3

Let base = 5 a meters and altitude be 3 a meters

Area will then be equal to 5 a * 3 a = 15 a² meter² = 50 meter²

So a² = 50/15 a = √3.33

The altitude of the parallelogram is = 3 a = 5.477 meters

base : altitude = 5 : 3

Let base = 5 a meters and altitude be 3 a meters

Area will then be equal to 5 a * 3 a = 15 a² meter² = 50 meter²

So a² = 50/15 a = √3.33

The altitude of the parallelogram is = 3 a = 5.477 meters