A spherical airbubble is formed in water at a depth of 1metre from its surface .s surfacetention of water is 75.calculate the pressure inside the bubble ,if pressure of air over the surface of water is 0.78meter of mercury










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radius of bubble is missing.
surface tension is 75 cgs units, 0.075 N/meter

Answers

2014-10-07T16:02:09+05:30

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Pressure inside bubble in air - Pressure outside the bubble in water = 
                  = 2 * Surface tension / Radius of bubble

P₂ - P₁ = 2 S / R

P₁ = Pressure outside the water surface + Pressure due to water column of 1meter
      = 0.78 meter * Density of mercury * g + 1 meter * density of water * g
      = 0.78 m * 13,546 kg/m³ * 9.81 m/s² + 1 m * 1000 kg/m³ * 9.81 m/s²
      = 103,651.283 + 9810 = 113461.283  Pa

P₂ = P₁ + 2 S / R = 113,461.283 + 2 * 0.075 / R = 113,461.283 Pascal + 0.15/R 

               where R is the radius of bubble in meters

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