Answers

2014-10-08T18:40:06+05:30
Dx/dФ=3acos^2Ф * (-sinФ)

now 
dy/dФ=3bsin^2Ф * (cosФ)
so....................
dy/dx=-b/a * tanФ

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2014-10-08T18:44:16+05:30
X=acos³Ф
therefore,dx/dФ=3acos²Ф(-sinФ)
likewise,dy/dФ=3bsin²Ф(cosФ)
Now,dy/dx=-b/a*tanФ
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