# Between 1 and 31 are inserted 'm' arithmetic means, so that the ratio of 7th and [m-1]th means is 5:9 then find m ?

2
by vipulbinnu
[m-1]th means or [m-1]th terms
i don't know but he answers is coming in fraction

2014-10-09T17:05:26+05:30
K th Arithmetic mean of a sequence of A.P  , Where n is total number of A.M's b/w a and b .
Here,
a = 1 , b = 31  and n = m
A/Q,
7th  A.M : (m-1)th A.M = 5:9
or,
or,

or,

or,

or,

therefore
2044/146 = 14 always not in fraction.
yeah i think i do this type of sum by taking the upper value
karthik u r answer is absolutely correct.
ok i got my mistake
2014-10-09T17:48:54+05:30

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In an arithmetic series, we have n terms, or m+2 terms as in :

We have m = (n - 2) arithmetic means.      The common difference is

d = 30/15 = 2
The arithmetic series is 1, 3, 5, 7 ,...  27, 29, 31
There are totally 16 terms in this series.   There are 14 arithmetic means in between 1 and 31.