# A man weighs 70kg. He stands on a weighting machine in a lift, which is moving (a) Upwards with a uniform speed of 10m/s. (b) Downwards with a uniform acceleration of 5m/s2. (c) Upwards with a uniform acceleration of 5m/s2. Take g = 9.8m/s2. What would be the readings on the scales in each case what would be the reading if the lift mechanism failed and it came down freely under gravity? CLASS - XI PHYSICS (Laws of Motion)

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by prachiSarin356

2014-10-10T15:17:41+05:30

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A) the forces acting on body = weight of person = 70*9.8 = 686 N

weighing machine will show = 686/9.8 = 70 kg
b)force acting on body = weight of person + upward pseudo force
= 70*9.8 - 70*5 = 336 N
weighing machine will show = 336/9.8  = 34.28 kg
c)force acting on body = weight of person + downward pseudo force
= 70*9.8 + 70*5 = 1036 N
weighing machine will show = 1036/9.8  = 105.71 kg