Answers

2014-03-10T13:21:07+05:30
Let the three no. be x,x+1,x+2
according to the question
3(x+1)=x+x+2+11
3x+3=2x+13
x=10
the three no. are 10,11,12
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2014-03-10T18:23:17+05:30
Let three consecutive number be a, a+d, a+2d

3(a+d) = a+a+2d+11
3a+3d = 2a+2d+11
3a-2a+3d-2d=11
a+d=11

The middle number is 11
Therefore the 3 consecutive nos are 10,11,12
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