# Solve -4+[-1]+2........+x=437

2
by brindha

2014-10-10T16:09:59+05:30

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It is an arithmetic series.

a = -4    d = +3
-4  - 1  + 2  + 5 + .... + (x-3) + x = 437

Sum of the series = [ 2 a + (n-1)d ]n /2 = 437
[ - 8 + 3(n-1) ] n / 2  = 437
- 11n + 3n² = 874
3 n² -11n - 874 = 0
n =   (11 +- 103 )/6  =  114/6 = 19   as n is +ve only.

So x = a + (n-1)d = -4 + 3 (19-1) = 50

-4-1+2...+x=437
sorry it's done by mistake
2014-10-10T16:46:42+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
First term(a) = - 4
common difference(d) = 3
- 4  - 1 + 2 + 5 + .... + x = 437

so now using formula for sum of n terms

⇒437= n/2[ -8 + (n-1)3]
⇒n[ -8 + 3(n-1) ] = 874
⇒ -11x=n + 3n² = 874
⇒3n² -11n - 874 = 0
Using sidharacharya
no. of terms cannot be negative the we take the positive value
n = 19
So
x = a + (n-1)d = -4 + 3 (19-1) = 50