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2014-10-11T16:19:12+05:30

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Let the initial velocity be u m/s.  angle of projection = 0

initial component of velocity in vertical direction = 0

horizontal displacement from initial position at t= 0sec,   = x = u t 
vertical displacement from initial position at t = 0 0sec,   =  y = -1/2 g t²

so t = x/u

Hence        y = - 1/2 g (x/u)² = - (g/2u²)  x²

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