# 1)Given tan(A+B)=1, tan(A-B)=1/7. Find tan A and tan B. 2)Compute cosec(13pie/12). given in radians...Answer is -sqrt(6)-sqrt(2).Pls explain..

1
by nikhils647
is the answer for the 2 nd question -(sqrt(6)-sqrt(2))
Yes

• Brainly User
2014-10-11T21:06:56+05:30
1)
Tan ( A + B ) =  = 1

Tan ( A - B ) =

on adding Tan ( A + B )  and  Tan ( A - B ) we get 8 Tan A + 6 Tan B = 2

4 Tan A + 3 Tan B = 1

on substituting Tan A in Tan ( A + B ) we get

+ 8 Tan B - 3 = 0

then Tan B =  or -3

If Tan B is considered as  Tan A is

If Tan B is considered as -3 , Tan A = -2

If Tan B is considered as  Tan A is

the question is to find tanA and tan B
i posted it by mistake i am editing the answer
where is tan A?
it is given that If Tan B is considered as 1/ 3 Tan A is 3 / 4 and if If Tan B is considered as -3 , Tan A = -2