Answers

  • Brainly User
2014-10-11T21:06:56+05:30
1) 
Tan ( A + B ) =  \frac{Tan A + Tan B}{1 - Tan A * Tan B} = 1

Tan ( A - B ) =   \frac{Tan A - Tan B}{1 + Tan A * Tan B}  \frac{1}{7}

on adding Tan ( A + B )  and  Tan ( A - B ) we get 8 Tan A + 6 Tan B = 2

4 Tan A + 3 Tan B = 1

on substituting Tan A in Tan ( A + B ) we get

 Tan^{2} B + 8 Tan B - 3 = 0

then Tan B =  \frac{1}{3} or -3

If Tan B is considered as  \frac{1}{3} Tan A is  \frac{3}{4}

If Tan B is considered as -3 , Tan A = -2

If Tan B is considered as  \frac{1}{3} Tan A is  \frac{3}{4}

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the question is to find tanA and tan B
i posted it by mistake i am editing the answer
where is tan A?
it is given that If Tan B is considered as 1/ 3 Tan A is 3 / 4 and if If Tan B is considered as -3 , Tan A = -2