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## Answers

__3/x+1/y=7__

__or,3y+x=7__

__or,x=7-3y......................(1)__

__5/x -4/y=6__

__or,5y-4x=6__

__putting the value of x as 7-3y from (1) we have,__

__5y-(28-12y)=6__

__or,17y=6+28=34__

__or, y=34/17=2............(2)__

__x=7-3y__

__Putting the value of y as 2 from (2) we have,__

__x=7-6=1__

__Ans: y=2__

__x=1__3*(1/y) + 1/y = 7 -----(2)

5/x - 4/y = 6 -----(3)

5*(1/x) - 4*(1/y) = 6 ----(4)

let 1/y = p and 1/y = q ---(5)

(5)in (2)and(4)=>

3p+q=7 ----(6)

5p-4q=6-----(7)

from (6)

q=7-3p -------(8)

(8)in(7)=>

5p - 4(7-3p) = 6

5p - 28 + 12p = 6

17p = 6+28

17p=34

p=34/17

=2 -----(9)

(9) in(8)=> q=7 - 3*2=7-6=1

we have p=1/x

2=1/x

2x=1

x=1/2

we have q=1/y

1=1/y

y=1

solution x=1/2

y= 1