# What is the angle of projection at which horizontal range and maximum height are equal? CLASS - XI PHYSICS (Kinematics)

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2014-10-12T14:42:01+05:30

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Let the required angle be β.

Range =

maximum height =

So

⇒tan β = 4
⇒ β = arctan(4)
⇒ β = 75.96⁰

2014-10-12T18:06:32+05:30

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In kinematics we have the following formulas for the projectile motion:
It is useful to remember them or to derive them quickly.

time to reach the highest point = (u sin Ф /g)

R = 2 (u Sin Ф /g )(u cos Ф) = u² Sin 2Ф / g

H = (u sin Ф / g) (u Sin Ф/2) = u² Sin² Ф / 2g

H / R = tan Ф / 4

If H = R then    tan Ф = 4     =>  Ф = 75.96°