# Lock of mass 10kg is sliding on a surface inclined at a angle of 30o with the horizontal. Calculate the acceleration of the block. The coefficient of kinetic friction between the block and the surface is 0.5 CLASS - XI PHYSICS (Laws of Motion)

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• Brainly User
2014-10-22T23:06:46+05:30
A=g[sinθ - μcosθ] Answer: 0.669m/s for g=10
2014-10-29T08:57:10+05:30

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See diagram.
resolve mg = weight of block  in two directions - along the plane and perpendicular to the plane.

N = mg Cos Ф             as there is no acceleration perpendicular to the incline

m a = mg Sin Ф - μ N = mg (Sin Φ - μ Cos Φ)

a = g (Sin Φ - μ Cos Φ) = 9.81 (Sin 30 - 0.5 Cos 30)

acceleration of the block down the plane  = 9.81 (1/2 - 0.5 √3/2)
= 0.657 meters/sec²