Answers

2014-10-12T22:06:34+05:30
 acceleration is taken as constant
we know a = dv/dt
                 dv = a dt   
  Integrating both sides with proper limits 

 \int\limits^u_v \, dv= \int\limits^0_t {a} \, dt

 \int\limits^u_v \, dv=a \int\limits^0_t  \, dt

[v]^v_u=a[t]^t_0

v-u=at

v=u+at

second equation

a= dv/dt x dx/dx
a = v dv/dx
v dv = a dx 

  Integrating both sides with proper limits 

\int\limits^v_u {v} \, dv = \int\limits^s_0 {a} \, dx

\int\limits^v_u {v} \, dv =


[\frac{v^2}{2}]^v_u =a[x]^s_0

 v^{2}-u^{2} = 2as


2 4 2