# Rohit bought 20 oranges and 30 bananas for RS280 . if the cost of each orange got doubled , then he would have bought 30 oranges and 40 bananas for RS 540.find the cost of each orange.(in RS)

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Let cost of each orange = Rs. x

cost of each banana = Rs. y

Cost of 20 oranges and 30 bananas = 20x+30y

So 20x+30y = 280

⇒**2x + 3y = 28**

if cost of each orange is doubles, cost of each orange = 2x

cost of 30 oranges and 40 bananas = 30(2x) + 40y = 60x+40y

thus 60x+40y = 540

⇒**6x + 4y = 54**

Solving the two equations we get, x = 5 and y = 6.

So**cost of each orange = Rs. 5.**

cost of each banana = Rs. y

Cost of 20 oranges and 30 bananas = 20x+30y

So 20x+30y = 280

⇒

if cost of each orange is doubles, cost of each orange = 2x

cost of 30 oranges and 40 bananas = 30(2x) + 40y = 60x+40y

thus 60x+40y = 540

⇒

So

Cost of each banana = Rs y

Cost of 20 oranges and 30 bananas = 280

⇒20x+30y = 280

Dividing both sides by 10

⇒ 2x + 3y = 28 ........(1)

Cost of each orange is doubled.

Now, cost of orange = Rs 2x

Cost of 30 oranges and 40 bananas is Rs 540

60x + 40y = 540

Dividing both sides by 20

3x + 2y = 27 .......(2)

Multiply eq (1) by 2 and eq(2) by 3

4x + 6y = 56

9x + 6y = 81 (Subtract)

-----------------

-5x = - 25

x = 5

Cost of each organge = Rs 5