# I am thinking about two numbers having the same two digits. the sum of the two digits is 9 and the difference of the two numbers is 27. find the two numbers

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by utsa

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by utsa

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then two numbers will be 10a+b and 10b+a

from the problem,

a+b=9 and 10a+b-(10b+a)=27

take a+b=9 as 1st equation

by solving 10a+b-(10b+a)=27 we will get

a-b = 3 take this as 2nd equation

now add 1and 2 equations

a+b=9

a-b=3

2a=12 and a =6 then the value of b will be 3

therefore the numbers are 63 and 36

Let 2 nos be x,y. x+y=9;x=9-y. now x-y=27; 9-y-y=27 (bcoz x=9-y) 2y= -18 y= -9 there4 x=18