# Number of prime factors of (3 x 5)12 (2 x 7)10 (10)25 is:

2
by arun407

2014-10-15T23:24:40+05:30

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The equation can be facorize as 3*5*3*2*2*2*7*2*5*2*5*5*5 or 2^5*3^2*5^5*7^1 total no of prime factor =(5+1)*(5+1)*(2+1)*(1+1)=216
The equation can be facorize as 3*5*3*2*2*2*7*2*5*2*5*5*5 or 2^5*3^2*5^5*7^1 total no of prime factor =(5+1)*(5+1)*(2+1)*(1+1)=216
2014-10-16T11:43:50+05:30

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Express the given number N as a product of prime numbers:

N

A prime factor of N is obtained by multiplying  (none or one or two or three or four or five of 2s ) * (none or one or two of 3s ) * (none or one or more of 5s ) * (none or one 7 )

So the number of distinct prime factors will be

= (1+5)(1+2)(1+5)(1+1)  = 6 * 3 * 6 * 2

= 216