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## Answers

ACCORDING TO mLOGX=LOGXm

log2³-log3²

log8-log9

log8/9(logx-logy=logx/y)

log2³-log3²

log8-log9

log8/9(logx-logy=logx/y)

**3log2-2log3**

**It is in the form of xlogy**

**formulae for it is logy^x**

**3 log 2-2 log 3=log(2)^3-log(3)^2**

**=log(8)-log(9)**

**It is in the form of loga-logb**

**formulae for it is log(a/b)**

**log(8)-log(9)=log(8/9)**