Answers

2014-10-18T21:20:46+05:30
ACCORDING TO  mLOGX=LOGXm
log2³-log3²
log8-log9
log8/9(logx-logy=logx/y)
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2014-10-18T21:23:48+05:30
3log2-2log3
It is in the form of xlogy 
formulae for it is logy^x
3 log 2-2 log 3=log(2)^3-log(3)^2
                        =log(8)-log(9)
It is in the form of loga-logb
formulae for it is log(a/b)
log(8)-log(9)=log(8/9)
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