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2014-10-19T00:06:06+05:30

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[ (2 y + 2 z) y ] - [ (x + y) (x + z) ]\\ \\=[ (2y + 2z) y + xy - yz ] - [ (x + y) (x + z) +xy - yz]\\ \\=[ (2y + 2z) y + y(x - z) ] - [ (x + y) (x + z) +xy + xz - yz - xz ]\\ \\=[ (2y+2z+x-z) y ] - [ (x + y) (x + z) +x (y+z) - z(x+y) ]\\ \\=[ (x+2y+z) y ] - [ (x + y) (x + z - z) +x (y+z) ]\\ \\=[ (x+2y+z) y ] - [ (x + y) (x) +x (y+z) ]\\ \\=[ (x+2y+z) y ] - [ (x + y+y+z) (x) ]\\ \\=(x+2y+z) (y-x)\\

2 5 2
no sir...plz give it in a detailed manner.....
(xy - yz) has been added in the first bracket and
sir plsss sir didnt understood this sum so plzz writ which formula u hv taken
i added and subtracted some terms. that is all.. i added xy - yz to the first term.. then i subtracted the same.. so second term also has xy-yz..
then I added and subtracted xz in the second term.. then factorized the first part and second part....