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## Answers

let f(x)=x2013

x2-1 can be resolved into factors as (x+1)(x-1)

now x+1=0 => x=-1

substitue x=-1 in f(x)

f(-1)= (-1)2013 =-1

then x-1=0 => x=1

sub x=1 in f(x)

f(1) = (1)2013 =1

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let f(x)=x2013

x2-1 can be resolved into factors as (x+1)(x-1)

now x+1=0 => x=-1

substitue x=-1 in f(x)

f(-1)= (-1)2013 =-1

then x-1=0 => x=1

sub x=1 in f(x)

f(1) = (1)2013 =1