Answers

2014-10-20T14:39:31+05:30
(x+1)^2-x^2 = 121
x^2+2x+1-x^2 = 121
x^2-x^2+2x+1 = 121
2x+1=121
2x=121-1
2x=120
x=120:2
x=60

So the numbers are 60 and 61.
let''s check :

61^2-60^2=121?
3721-3600 = 121 TRUE


0
which one i scorrect
ok, so..if you wrote the exercise correctly, then the answ is 61 and 60. if u forgot anything than ...it's not my problem anymore
then y u delete ma answer u also posted the same answer isn't it/
nope. you've done exactly the opposite
ive told you. you've wrote x^2-(x+1)^2. that's not the same. RIGHT?
2014-10-20T14:58:05+05:30
Let the two consecutive number be x and (x+1)
Then, A.T.Q.
(x+1)²-x²=121
x²+2x+1-x²=121
2x+1=121
2x=121-1
2x=120
x=120/2
x=60

Hence the first number is 60
AND
The second number is x+1= 60+1
=61

Therefore the two numbers are 60 and 61.

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