# Suppose while sitting in a parked car,you notice a jogger approaching towards you in the rear view mirror of R=2 m.if the jogger running in a speed of 5 m/s,how fast is the image of the jogger moving,when the jogger is (a) 39 m (b) 29 m (c) 19 m and (d) 9 m away? answer are 1/280,1/150,1/60,1/10

1
by dangerstriker47
tenth ka level ka base par ans. dana
did u learn differentiation or not..? if we do not use differentiation, then you find, v at each point and v after one second of time.. the difference will give an approximate or crude value.
i had only learn the fomulaes 1/f=1/u+1/v
r2f
m=hi/h0=-v/u

2014-10-23T07:49:54+05:30

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If u do not know differentiation, then : we can find approx values as:

similarly the last one.
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If u know differentiation, then you can derive the correct solution as below.

The rear view mirror is a convex mirror.1/v + 1/u = 1/f = 2/R = 1 Differentiating both sides

du / dt = - 5 m/sec

a)  u = -39 m

b) u = -29 m

c) u = -19 m

d) u = -9 m

i hope the solution is clear now