Answers

2014-10-21T20:51:00+05:30
Given one end of the diameter as (3,2)
 let A = (3,2) center O= (0,0)
let the other end's co ordinates B = (x,y)
mid point of ends of diameter = center of the circle
 (x+3/2, y+2/2) = (0,0)
 compare x co ordinates
x+3/2 = 0
x+3 = 0
x = -3
compare y co ordinates
y+2/2 = 0
y+2 = 0
y = -2
co-ordinates of another end B(x,y) = (-3,-2)
0