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Find the equation of the line whose y-intercept is 4 and parallel to the line 2x-3y-7=0

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by anudeepd2

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by anudeepd2

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So when lines are parallel their slopes are equal

m = m₁

so the slope of line 2x - 3y - 7 = 0 ,m₁ = -2/3

so using y = mx + c

y = (-2/3)x + 4

3y = -2x + 12

2x + 3y - 12 = 0__ANSWER__

m = m₁

so the slope of line 2x - 3y - 7 = 0 ,m₁ = -2/3

so using y = mx + c

y = (-2/3)x + 4

3y = -2x + 12

2x + 3y - 12 = 0

The Brainliest Answer!

this passes through (0,4)

2*0-3*4+c=0

=>c=12

line is 2x-3y+12=0.