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Find the equation of the line whose slope is 4/5 and which bisects te line joining the points P(1,2) and and Q(4,-3)

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by anudeepd2

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by anudeepd2

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So the midpoint of P and Q is

x = (1+4)/2 = 5/2

y = (2 - 3)/2 = -1/2

so the mid point be Z(5/2,-1/2)

so the line is

(y+1/2) = 4/5(x - 5/2)

⇒(2y + 1)/2 = 4/5(2x - 5)/2

⇒10y + 5 = 8x - 20

⇒8x - 10y - 25 = 0__ANSWER__

x = (1+4)/2 = 5/2

y = (2 - 3)/2 = -1/2

so the mid point be Z(5/2,-1/2)

so the line is

(y+1/2) = 4/5(x - 5/2)

⇒(2y + 1)/2 = 4/5(2x - 5)/2

⇒10y + 5 = 8x - 20

⇒8x - 10y - 25 = 0

The Brainliest Answer!

slope of the equation = 4/5

and passing through the line of points p(1,2) and q(4,-3)

the line bisects it means passing through the mid point.

mid point of points p(1,2) and q(4,-3) is

[ (1+4)/2 , (2-3)/2 ]

=( 5/2 , -1/2 )

so the line equation is ( y-y1 ) = m ( x-x1 )

( y+1/2 ) = 4/5 ( x-5/2 )

(2y+1)/2 = 4/5 (2x-5)/2

(2y+1)/2 = (8x-20)/10

(2y+1)5 = 8x-20

10y+5 = 8x-20

8x-10y-25=0