# An object 2cm high is placed at a distance of 16cm from a concave mirror which produces a real image 3cm high. what is focal length of the mirror and position of the image??????

2
Log in to add a comment

Log in to add a comment

size of the image = h2 = -3 cm

u = obj distance = -16 m

Therefore from formula -v/u = h2 / h1, we have

-v/(-16) = -3/2

v/16 = -3/2

v = -3* 16/2

v = - 24 cm

From mirror formula = 1/v + 1/u = 1/f

=> 1/-24 + 1/-16 = 1/f

=> 1/f = (-2 - 3)/ 48

=> 1/f = -5 / 48

=> f = - 48/5

= > f = - 9.6 cm

The Brainliest Answer!

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

Height of the object, h1 = 2 cm

height of the image, h2 = -3 cm

object distance, u = -16cm

image distance = v

magnification =

⇒

⇒

⇒

From mirror formula

So**focal length is 9.6cm and image distance is 24cm(to the left of mirror)**

height of the image, h2 = -3 cm

object distance, u = -16cm

image distance = v

magnification =

⇒

⇒

⇒

From mirror formula

So