Answers

  • Brainly User
2014-10-24T22:17:12+05:30
You have log(x)=(b/a)log(c) and log(x)=(a/c)log(c) From these b/a=a/c Hence, a^2=bc
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I don't think logarithms are required here, anyway this is the answer.
Please hwlp without log
Raise the power of first equation to 1/a and that of second to 1/c then you have x=c^(b/a)=c^(a/c)
Raise the power of first equation to 1/a and that of second to 1/c then you have x=c^(b/a)=c^(a/c) Equate the powers since the bases are same. Then you shall have a^2=BC
Thanks
2014-10-24T22:51:40+05:30

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 x^{a}= c^{b}   \\ x= ( c^{b} )^{ \frac{1}{a} }  \\ x=c^{ \frac{b}{a} }

 x^{c}= c^{a} \\ x=(c^{a})^{ \frac{1}{c} }  \\ x= c^{ \frac{a}{c} }

thus
 c^{ \frac{b}{a} }=c^{ \frac{a}{c} }   \\  \frac{b}{a} = \frac{a}{c}  \\  a^{2}=bc
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