# A cubical block of water is dipped completely in water. Each edge of the block is 1cm in length. Find the buoyant force acting on the block

2
by princey

2014-10-26T17:35:33+05:30

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Length of edge of cubical ice block = 1 cm
volume of the block (V)= 1³ cm³ = 10^(-6) m³
density of water (Dw)= 10³ kg/m³

buoyant force = Dw×V×g = 10³ × 10^(-6) × 10 = 10^(-2) N = 0.01 N

2014-10-27T14:32:33+05:30

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Buoyant force acting vertically upwards on the object = weight of the water displaced
= density of water * volume of block * g = 1 gm / cm³ * 1cm³ * 981 cm/sec²
= 981 dynes
= 0.00981 Newtons