1)the probability of getting a tail on throwing a unbiased coin is ......................

2)the probability of getting a head on throwing a unbiased coin is......................

3)in one thousand lottery tickets ,there are 50 prizes to be given.the probability that venkatesh winning a prize ,who bought one ticket is

a)1/50 b)1/1000 c)1/20 d)1/10

4)the probability that a non-leap year has 53 sundays ,is

a)6/7 b)5/7 c)2/7 d)1/7

5)the probability that a leap year has 52 Mondays

a)3/7 b)2/7 c)6/7 d)5/7

STATISTICS

1)the arithmetic mean of first 'n' natural numbers

a)n/2+1 b)(n-1)/2 c)(n+1)/2 d)n/2

2)the mean of first 'n' odd natural numbers

a)n/2 b)n c)n² d)(n+1)/2

3)ogive can be used to find ..........................of a frequency.

4)the mode of a frequency distribution can be determined graphically from ............................

5) an ogive is a graphical representation of ...................................

6)if the mean of of scores 12,15,x, 19,25 and 44 is 25 then x=..........................




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Answers

2014-10-27T11:52:23+05:30

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1).  There are two possible outcomes - head and tail.    What we want is one outcome.   So the probability is 1 / 2 

2).  Same as in (1).  the probability = 1 / 2

3).  50 persons are given prizes.  there are totally 1000 persons.  So probability is 50/1000 = 1/20

4). In a non-leap year there are 365 days.  There are 52 weeks. In 52 weeks, we have 364 days.  that extra one day (365th) can be any week day of the 7.  So  probability that it is a Sunday is 1/7.

5)  Probability that there are 52 Mondays = probability that 365th day is one of Tuesday to Sunday.  =  6/7.
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1) Average of the 1st n natural numbers = (1st number + last number) / 2
      = (1+n)/2    not including 0 as 1st natural number.   They are in A.P.

2)  first n odd numbers :  1 , 3 , 5 ..  2 n - 3,  2 n - 1
       it is also A.P.    Average = (1+2 n - 1)/2 = n

3)  the probability of a frequency (interval)

4)  

5)  Ogive represents graphically the cumulative probability distribution of frequency intervals

6)  25 * 6 = 150 = 12+15+x + 19+25+44   => x = 35


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