# Three resistors of 3Ω, 1.5Ω and 1Ω are connected in parallel. calculate the current in each of the resistors. the voltage of the battery they are connected to is 4.5 volts.

2
by Nitya8

2014-10-27T19:39:27+05:30
for 3 ohm I=V/R = 4.5/3 =1.5A ,
for 1.5 ohm I= 4.5/1.5 = 3A and
for 1 ohm I= 4.5/1 =4.5A
i need the currents of all the three resistors not the current of the main wire :)
for 3 ohm I=V/R = 4.5/3 =1.5A , for 1.5 ohm I= 4.5/1.5 = 3A and for 1 ohm I= 4.5/1 =4.5A
what if the parallel is connected to a resistor in series whose resistance is 8.5 ohm. will the answer be the same?
Nitya, u need to click on "Ask our moderators to review it" blue link, when u find a mistake i n an answer.
2014-10-27T19:53:21+05:30
As we know that V=IR
Potential across parallel remain same means potential drop across on 3 resistance will be same
Current in 3 ohm is given by =V/R=4.5/3=1.5 A
Current in 1.5 ohm is given by =4.5/1.5=3 A
Current in 1 ohm resistance is given by=4.5 A
and by the way its not bhai
Then effective resistance of the 3 parallel resistors is = 1 / (1+1/3+2/3) = 1/2 ohm. Total effective resistance in the circuit is 8.5 + 0.5 = 9 ohms. Current in the 8.5 ohms = 4.5/9 = 0.5 amp. Voltage across 3 parallel resistors is = 0.5*0.5 = 0.25 Volts. Now current in 1 ohm resistance is = 0.25 amp. Current in 3 ohms resistance is = 0.25V/3 = 1/12 amp. The current in 1.5 ohms resistor is 0.25/1.5 = 1/6 amp.
ok nitya
Now,Our effective resistance of three parallel resistor become a single resistance and this resistance is connected to 8.5 ohm with series, then effective resistance will be change
thanku Kvnmurthy