32 km above surface and 64 km below the surface. Both
g = acceleration due to gravity at surface of Earth
Re = radius of Earth
Me = Mass of Earth
Acceleration due to gravity " g' " at a height h above the surface
Hence gravity is less by 1% at a height of 32 km above the surface of Earth.
=============================================Below the surface of Earth
Let us assume that the density of Earth is uniform below surface. Then
Density of Earth = d = Me / (4πRe³/3)
Let us take a depth of h
below the surface of Earth.
Mass M of Earth enclosed within the radius of r = (R-h) contributes towards gravity at the depth h. The volume of Earth in the spherical shell of width h does not contribute to the gravity. This is because all the mass around the shell attracts the mass from all sides and the net effect is zero.
Hence, gravity is 1% less at a depth of 64 km under the surface