# The width of a rectangle is two/third of its length if the perimeter of the rectangle is 135cm find the dimensions of the rectangle

2
by salwa

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by salwa

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Width=(2/3)x

Perimeter of rectangle =135

2(l+b)=135

2(x+(2/3)x)=135

2((3x+2x)/3)=135

2(5x/3)=135

10x/3=135

10x=135*3

x=405/10=40.5

Width=2/3*40.5=27

Lenght=40.5

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So the length be x

so width = 2/3 x

so perimeter = 2(length + width)

135 = 2(x+2/3x)

5/3x × 2 = 135

x = (135 x 3) / (5 × 2)

x = 40.5 cm

so length = 40.5 cm and width = 2/3 x 40.5 = 27 cm

so width = 2/3 x

so perimeter = 2(length + width)

135 = 2(x+2/3x)

5/3x × 2 = 135

x = (135 x 3) / (5 × 2)

x = 40.5 cm

so length = 40.5 cm and width = 2/3 x 40.5 = 27 cm