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Let the speed of train = x km/h
time taken = 360/x hour
if speed has been 5 km/h more,
speed = x+5
time taken will be = 360/(x+5) hour

According to the question,

 \frac{360}{x} -\frac{360}{x+5}= 1 \\  \\ \frac{360*5+360x-360x}{x(x+5)} =1 \\  \\ 1800=x(x+5) \\  \\  x^{2} +5x-1800=0
Solving we get x= 40 km/h
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