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Charge on one electron = -1.6×10^(-19) C

no. of electrons =  \frac{2.4*10^{-18}}{1.6*10^{-19}} = \frac{24}{1.6} =15

Since the charge on the conductor is positive, the conductor is 15 electrons short.
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if 2 conductors are rubbed against each other and one has negative charge then the transfer of electrons is from which to which
electrons will be transferred from the conductor which is negatively charged to the other one.
thanks a lot