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## Answers

√5x - 2√5 = 10

Squaring both sides

(√5x - 2√5)² = 10²

5x² - 20x + 20 = 100

5x² - 20x - 80 = 0

x² - 4x - 16 = 0

using sidharacharya

we get x =

so we get

x =

√5x - 2√5 = 10

Squaring both sides

(√5x - 2√5)² = 10²

5x² - 20x + 20 = 100 [ using (a-b)² identity]

5x² - 20x - 80 = 0

x² - 4x - 16 = 0 [ Dividing by 5]

by quadratic formula

D=b²-4ac

=16+64

=80

X=

__-b-√D__or

__-b+√D__

2a 2a

x=

__4-√80__0r

__4 +√80__

2 2

x=

__4-4√5__or

__4+4√5__

2 2

x=2-2√5 0r 2+2√5